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x^2-500x-500000=0
a = 1; b = -500; c = -500000;
Δ = b2-4ac
Δ = -5002-4·1·(-500000)
Δ = 2250000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2250000}=1500$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-500)-1500}{2*1}=\frac{-1000}{2} =-500 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-500)+1500}{2*1}=\frac{2000}{2} =1000 $
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